Calculate the current
through the galvanometer when a potential difference of 10 V is maintained
across AC as shown in the image.
SOLUTION:
KIRCHHOFF'S SECOND LAW:
Kirchhoff's subsequent(second) law is otherwise called Voltage law (OR) Loop law.This law depends on LAW OF CONSERVATION OF ENERGY.Kirchhoff's subsequent law expresses that " THE ALGEBRAIC SUM OF ALL THE POTENTIAL DIFFERENCES ALONG A CLOSED LOOP IS ZERO".
CONVENTIONS:
Accept any course (direction) as the heading of traversal (direction of traversal). (Either clockwise or anticlockwise)
EMF of the cell is POSITIVE in the event that the bearing of the crossing (direction of the traversal) is from its NEGATIVE terminal to POSITIVE terminal. (NPP)
EMF of the cell is NEGATIVE assuming the heading of the crossing (direction of the traversal) is from its POSITIVE terminal to NEGATIVE terminal of the battery. (PNN)
The IR item is taken as POSITIVE on the off chance that the resistor is crossed a similar way as the expected to be current. (If the resistor is traversed in the same direction as the assumed current.)
POTENTIOMETER EXPERIMENT/K12 CBSE PHYSICS COMPARISON OF EMF OF TWO CELLS: EXPERIMENTAL SET UP : CIRCUIT DIAGRAM: CONDITIONS: SIMPLE CIRCUIT DIAGRAM: DOUBLE POLE DOUBLE THROW SWITCH CONNECTIONS : POTENTIAL GRADIENT : For better outcomes,utilize newly pre-arranged(freshly prepared) cell in any case, the polarization impact will happen which is segregating boundaries foster a connection point among cathode and electrolyte. The sensitivity of the potentiometer relies upon a potential gradient (K).If the potential gradient is little then the potentiometer is supposed to be more precise and delicate. PROCEDURE: This is the least complex circuit and every one of the connections are made as displayed previously. Connect the positive terminals of the auxiliary battery and primary cells to point A of the potentiometer (zero point). To actually look at the rightness(correctness) of the circuit,the pencil jockey is pressed close to the end A and B of the potentiometer.If the gal...
NEET PHYSICS TEST ARRANGEMENT: QUESTION: A capillary tube of radius 'r' is immersed in water and the water rises it to a height h.The mass of the water in the capillary tube is 5 g. Another capillary tube of radius '2r' is immersed in water.The mass of the water that will rise in the tube is; [A]. 2.5 g [B]. 5.0 g [C]. 10.0 g [D]. 20.0 g ANSWER: ANSWER - [C] SOLUTION: CAPILLARY RISE: A capillary tube (glass tube) of radius 'r 'is dipped in water, the surface pulls the capillary walls in downward direction. Capillary walls pull the surface in upward direction. By the way the water in the tube will rise above the adjacent liquid level till the forces get balanced. This rises what we called it as capillary rise WHAT ARE THE TWO FORCES ACTING AT EQUILIBRIUM? 1. First one is the weight of the water column, acting downwards. ...
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