Calculate the current
through the galvanometer when a potential difference of 10 V is maintained
across AC as shown in the image.
SOLUTION:
KIRCHHOFF'S SECOND LAW:
Kirchhoff's subsequent(second) law is otherwise called Voltage law (OR) Loop law.This law depends on LAW OF CONSERVATION OF ENERGY.Kirchhoff's subsequent law expresses that " THE ALGEBRAIC SUM OF ALL THE POTENTIAL DIFFERENCES ALONG A CLOSED LOOP IS ZERO".
CONVENTIONS:
Accept any course (direction) as the heading of traversal (direction of traversal). (Either clockwise or anticlockwise)
EMF of the cell is POSITIVE in the event that the bearing of the crossing (direction of the traversal) is from its NEGATIVE terminal to POSITIVE terminal. (NPP)
EMF of the cell is NEGATIVE assuming the heading of the crossing (direction of the traversal) is from its POSITIVE terminal to NEGATIVE terminal of the battery. (PNN)
The IR item is taken as POSITIVE on the off chance that the resistor is crossed a similar way as the expected to be current. (If the resistor is traversed in the same direction as the assumed current.)
COMPOUND MICROSCOPE: Compound microscope is a microscope uses the mix of two lenses to deliver a higher magnification.it is utilized in labs and principally utilized for the examination purpose.The absolute amplification created by a compound microscope not entirely settled by duplicating the amplification of the two lenses (objective and eye piece lens) CONSTRUCTION: There are two lenses joined in a compound magnifying instrument (microscope) which permits a lot higher amplification. The compound magnifying instrument (microscpe) comprises of a long barrel shaped cylinder where one finish of the cylinder has an objective lens (small aperture and small focal length) and the opposite end has an eyepiece lens (the aperture and the focal length are fairly bigger than the objective lens). Objective lens which centers a genuine picture of the object,the picture is additionally amplified by the eyepiece which gives the watcher a picture that is virtual, amplified and reversed (inv...
FACTORS THAT AFFECT THE FLIGHT OF A PROJECTILE: Projection point(angle) : The article is leaned at a point to the vertical or flat (horizontal) (close to the earth) The mass of the article: The flight condition incorporates no data about the item size, shape, or mass. Dispatch speed: Maximum stature (height) changes as the square of the dispatch speed (launch velocity). Multiplying the dispatch speed creates multiple times the greatest stature. Gravitational speed increase: It is the rate at which an article's speed is evolving. The change can be the means by which quick the article is moving,a bearing change or both. Air opposition: Effects will be disregarded. The drag of the air: Drag relies upon air thickness and the square of the velocity.If the drag is overlooked, the flight relies upon starting speed and speed increase due to gravity(near the earth).
NEET PHYSICS TEST ARRANGEMENT: QUESTION: A capillary tube of radius 'r' is immersed in water and the water rises it to a height h.The mass of the water in the capillary tube is 5 g. Another capillary tube of radius '2r' is immersed in water.The mass of the water that will rise in the tube is; [A]. 2.5 g [B]. 5.0 g [C]. 10.0 g [D]. 20.0 g ANSWER: ANSWER - [C] SOLUTION: CAPILLARY RISE: A capillary tube (glass tube) of radius 'r 'is dipped in water, the surface pulls the capillary walls in downward direction. Capillary walls pull the surface in upward direction. By the way the water in the tube will rise above the adjacent liquid level till the forces get balanced. This rises what we called it as capillary rise WHAT ARE THE TWO FORCES ACTING AT EQUILIBRIUM? 1. First one is the weight of the water column, acting downwards. ...
Comments
Post a Comment